5y^2+4y+17=0

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Solution for 5y^2+4y+17=0 equation: 



5y^2+4y+17=0

a = 5; b = 4; c = +17;
Δ = b2-4ac
Δ = 42-4·5·17
Δ = -324
Delta is less than zero, so there is no solution for the equation

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